#46 open
Richard Wiseman

Hash/$H documentation contradiction

Reported by Richard Wiseman | March 13th, 2009 @ 12:21 PM

Hopefully it's OK to submit documentation enhancements here - apologies if it's not!

On the $H page it says: "A convenience wrapper around the Hash constructor, with a safeguard that lets you pass an existing Hash object and get it back untouched (instead of uselessly cloning it)."

On the Hash page it says: "The $H(object) shortcut is now completely equivalent to new Hash(object). Both always return a new object, regardless of whether the argument was an Object or another Hash."

Unless I'm interpreting these wrongly, they mean the opposite to each other: where hash is an instance of Hash, the first says $H(hash)==hash; the second says $H(hash)!=hash.

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